Concrete & Masonry / Sonotube

Concrete Column Calculator

Larger round forms — porch columns, pier foundations, drilled piers. Same geometry as a Sonotube; the defaults are a 16″ column at 8 ft. For square columns use the slab calculator with the column footprint as length × width.

8″ · 10″ · 12″ · 16″ standard
below frost line + above grade
Waste
Order · incl. wasteCONCRETE · column
1.82yd³

Order 2.00 yd³ ready-mix — plants ticket in ¼-yd³ and most charge a short-load fee under ~5 yd³.

Net volume (44.7 ft³)
1.65 yd³
Waste 10%
+ 0.17 yd³
Ready-mix ticket
2.00 yd³
Approx. weight
6,702 lb
What to buy
80 lb bags
82
60 lb bags
110
40 lb bags
164
Est. delivered
Materials + delivery$5.50–$8 / bag · Sep 2026
$451 – $656
Installed (with labor)typ. $1,261
$906 – $1,839
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How to calculate sonotube by hand

Cubic feet per tube = π × (Diameter (in) ÷ 24)² × Height (ft) · 80 lb bags = ft³ ÷ 0.60

Worked example

  1. Radius: 12 in ÷ 2 = 6 in = 0.5 ft.
  2. Per tube: π × 0.5² × 4 ft = 3.14 ft³.
  3. Six tubes: 3.14 × 6 = 18.8 ft³; with 10% waste 20.7 ft³ = 0.77 yd³.
  4. Bags: 20.7 ÷ 0.60 = 35 × 80 lb bags (about 6 per tube) — under 1 yd³, so bags.
Field reference
8″ tube
0.35 ft³ per ft · 0.6 × 80 lb bags per ft
10″ tube
0.55 ft³ per ft · 0.9 bags per ft
12″ tube
0.79 ft³ per ft · 1.3 bags per ft
16″ tube
1.40 ft³ per ft · 2.3 bags per ft

Questions crews ask

How much concrete is in a 16-inch column?

1.40 ft³ per foot of height, so an 8 ft column is 11.2 ft³ = 0.41 yd³ each. Four of them are 1.66 yd³ — order 1.75 yards with waste; that is a short load, not a bag job.

How do I calculate concrete for a square column?

Width × depth × height, all in feet. A 12 × 12″ column 8 ft tall is 1 × 1 × 8 = 8 ft³ = 0.30 yd³. The slab calculator does this if you enter the footprint as length and width and the height as thickness in inches.

What psi concrete for columns?

3,000 psi for porch and pier columns; 4,000 psi or per the engineer for structural columns, which will also have a specified rebar cage. Vibrate or rod round forms to eliminate voids against the form.